-12b^2-8b=0

Solution for -12b^2-8b=0 equation:

-12b^2-8b=0

a = -12; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·(-12)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*-12}=\frac{0}{-24}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*-12}=\frac{16}{-24}
=-2/3
$